vomiting

How to calculate sodium deficit in dehydration?

vomiting treatment

Hyponatremic Dehydration (Na <130 mEq/L)

Here you calculate sodium deficit explicitly:Naโบ deficit (mEq)=(135โˆ’Serum Na)ร—0.6ร—weight (kg)\textbf{Naโบ deficit (mEq)} = (135 – \text{Serum Na}) \times 0.6 \times \text{weight (kg)}Naโบ deficit (mEq)=(135โˆ’Serum Na)ร—0.6ร—weight (kg)

๐Ÿ‘‰ 135 mEq/L is taken as desired Na


Example

10 kg child, Na = 125 mEq/L(135โˆ’125)ร—0.6ร—10=10ร—6=60 mEq(135 – 125) \times 0.6 \times 10 = 10 \times 6 = \textbf{60 mEq}(135โˆ’125)ร—0.6ร—10=10ร—6=60 mEq


Important

  • Correct slowly over 24โ€“48 hrs
  • Max rise: โ‰ค8โ€“10 mEq/L/day
  • Give via DNS / NS + added Na as needed

Isonatremic Dehydration (Na 130โ€“150)

No sodium deficit calculation needed

Instead calculate:

  • Fluid deficit = % dehydration ร— weight ร— 10

Example:

  • 10% dehydration in 10 kg child โ†’
    = 10 ร— 10 ร— 10 = 1000 mL deficit

Give:

  • Deficit + maintenance + ongoing loss
  • Usually NS / RL initially

Hypernatremic Dehydration (Na >150)

๐Ÿ‘‰ Do NOT calculate sodium deficit
Instead calculate free water deficit:Water deficit (L)=0.6ร—wtร—(Na145โˆ’1)\textbf{Water deficit (L)} = 0.6 \times \text{wt} \times \left(\frac{\text{Na}}{145} – 1\right)Water deficit (L)=0.6ร—wtร—(145Naโ€‹โˆ’1)


Example

10 kg child, Na = 1600.6ร—10ร—(160/145โˆ’1)โ‰ˆ6ร—0.103=0.62 L0.6 \times 10 \times (160/145 – 1) \approx 6 \times 0.103 = \textbf{0.62 L}0.6ร—10ร—(160/145โˆ’1)โ‰ˆ6ร—0.103=0.62 L


Key Pediatric Pearls (Exam Gold)

  • Hyponatremia โ†’ calculate Na deficit
  • Hypernatremia โ†’ calculate water deficit
  • Isonatremia โ†’ calculate fluid deficit only

Correction Rules

  • Hyponatremia: โ†‘ Na โ‰ค8 mEq/day
  • Hypernatremia: โ†“ Na โ‰ค10โ€“12 mEq/day
  • Rapid correction โ†’ ODS (hypo) / cerebral edema (hyper)

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